2x^2+3xy+y^2=3

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Solution for 2x^2+3xy+y^2=3 equation: 


Simplifying
2x2 + 3xy + y2 = 3

Reorder the terms:
3xy + 2x2 + y2 = 3

Solving
3xy + 2x2 + y2 = 3

Solving for variable 'x'.

Reorder the terms:
-3 + 3xy + 2x2 + y2 = 3 + -3

Combine like terms: 3 + -3 = 0
-3 + 3xy + 2x2 + y2 = 0

The solution to this equation could not be determined.

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